Continuity of Piecewise Functions — Determining Continuity
2:08
Continuity of Piecewise Functions — Determining Continuity
5.5K views1 month ago
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Q) If 𝑦=sin⁡(𝑥+𝑦) and 𝑑𝑦/𝑑𝑥=0, then prove that 𝑦=±1.#class12maths
1:57
Q) If 𝑦=sin⁡(𝑥+𝑦) and 𝑑𝑦/𝑑𝑥=0, then prove that 𝑦=±1.#class12maths
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Find k so that 𝑓(𝑥)={((𝑥^2−2𝑥−3)/(𝑥+1), 𝑥≠−1 𝑘, 𝑥=−1) is continuous at x=−1.#cbse2027 #maths
2:22
Find k so that 𝑓(𝑥)={((𝑥^2−2𝑥−3)/(𝑥+1), 𝑥≠−1 𝑘, 𝑥=−1) is continuous at x=−1.#cbse2027 #maths
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Q) If sin^(−1) 𝑥=𝑦,then 𝑑𝑦/𝑑𝑥 is #maths #continuityanddifferentiabilityclass12 #class12 #cbse
0:56
Q) If sin^(−1) 𝑥=𝑦,then 𝑑𝑦/𝑑𝑥 is #maths #continuityanddifferentiabilityclass12 #class12 #cbse
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Q) If 𝑓(𝑥)={(3𝑥−2, 0≤𝑥≤1 2𝑥^2+𝑎𝑥, 1≤𝑥≤2) is continuous for 𝑥∈(0,2), then a is equal to
1:09
Q) If 𝑓(𝑥)={(3𝑥−2, 0≤𝑥≤1 2𝑥^2+𝑎𝑥, 1≤𝑥≤2) is continuous for 𝑥∈(0,2), then a is equal to
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Q) If 2cos^(−1) x=y, then dy/dx is #continuity_and_differentiability #maths #cbsemaths #cbse2027
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Q) If 2cos^(−1) x=y, then dy/dx is #continuity_and_differentiability #maths #cbsemaths #cbse2027
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YouTubeShivang Maths Academy
Q) Find the value of k, so that f(x)={ ((kcos x)/(𝜋−2x),if x≠𝜋/2 3, if x=𝜋/2) is contin
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Q) Find the value of k, so that f(x)={ ((kcos x)/(𝜋−2x),if x≠𝜋/2 3, if x=𝜋/2) is contin
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YouTubeShivang Maths Academy
2:29
Q) If 𝑦=cos^(−1)⁡{(2𝑥−3√(1−𝑥^2 ))/√13}, find 𝑑𝑦/𝑑𝑥. #maths #cbse2027 #cbse #continuityanddif
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Q) Show that the derivative of tan^(−1) (sec𝑥+tan𝑥),[−𝜋/2𝑥𝜋/2] with respect to x is equal to 1
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1:21
Q) If e^y (x+1)=1, prove that dy/dx=−e^y #cbseclass12 #cbse2027 #maths # #cbsenotes
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1:06
Q) If e^(𝑥+y)=3𝑥, then dy/d𝑥 is #maths #differentiation #cbse2026 #cbse2027
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Q) If 𝑦=sin⁡[2tan^(−1)⁡{√((1−𝑥)/(1+𝑥))}], find 𝑑𝑦/𝑑𝑥.#maths #cbse #cbsemaths #cbse2026
2.8K views1 month ago
YouTubeShivang Maths Academy
1:40
Q) If 𝑦=sin^(−1) {𝑥/√(𝑥^2+1)}, find 𝑑𝑦/𝑑𝑥. #cbseclass12 #maths #cbse2026 #cbse2027 #cbse
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Q) Find Integral∫〖√((𝑥+2)/(𝑥−2)) d𝑥〗
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2:47
Q) If 𝑥=cos t,y=cos mt, prove that (1−𝑥^2 )(d^2 y)/(d𝑥^2 )−𝑥 dy/d𝑥+m^2 y=0 #mathshorts #maths
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YouTubeShivang Maths Academy
1:38
Q) If ∫〖2^(1/𝑥)/𝑥^2 d𝑥〗=k⋅2^(1/𝑥)+C, then k is equal to
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